Given A is an acute angle and cosec A = √2, find the value of 2sin^A + 3cot^2A/tan^2 - cos^2A

Question

KnowledgeBoat · Accepted Answer

Let triangle ABC be a right-angled at B and A is a acute angle. Given, cosec A = ⇒ cosec A = = Let AC = k and BC = k. In right angled triangle ABC, By using pythagoras theorem, AC² = AB² + BC² ()² = AB² + k² 2k² = AB² + k² AB² = 2k² - k² AB² = k² AB = = k. By formula, sin A = = . tan A = = . cot A = . cos A = = . Substituting these values in we get, Hence, = 8.

Mathematics

Given A is an acute angle and cosec A = √2, find the value of 2sin^A + 3cot^2A/tan^2 - cos^2A

Trigonometrical Ratios

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