Mathematics
Given : ED = EC
Prove : AB + AD > BC.
Triangles
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Answer
We know that,
The sum of any two sides of the triangle is always greater than the third side of the triangle.
In △ CEB,
⇒ EC + EB > BC
⇒ ED + EB > BC (As, EC = ED)
⇒ BD > BC
In △ ADB,
⇒ AD + AB > BD
Since, BD > BC and AD + AB > BD
∴ AD + AB > BC.
Hence, proved that AB + AD > BC.
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