Given : sec A =29/21, evaluate : sin A - 1/tan A

Given: sec i.e. ∴ If length of AB = 21x unit, length of AC = 29x unit. In Δ ABC, ⇒ AC2 = AB2 \+ BC2 (∵ AC is hypotenuse) ⇒ (29x)2 = (21x)2 \+ BC2 ⇒ 841x2 = 441x2 \+ BC2 ⇒ BC2 = 841x2 \- 441x2 ⇒ BC2 = 400x2 ⇒ BC = ⇒ BC = 20x sin tan Now, Hence, .