Mathematics
Given : FB = FD, AE ⊥ FD and FC ⊥ AD.
Prove that :
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Answer
Given, FB = FD
∴ ∠FBD = ∠FDB [Since, opposite sides of equal angles are equal] ……(1)
In △AED and △FCB,
∠ADE = ∠FBC [From 1]
∠AED = ∠FCB [Both = 90°]
∴ △AED ~ △FCB [By AA]
Since, corresponding sides of similar triangles are proportional we have :
⇒ .
Hence, proved that .
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