Mathematics
In the given figure, AB || CD || EF. If AC = 7 cm, AE = 14 cm and BF = 20 cm, then DF is equal to:

7 cm
14 cm
10 cm
16 cm
Related Questions
If the quadrilateral formed by joining the mid-points of the adjacent sides of quadrilateral ABCD is a rectangle, show that the diagonals AC and BD intersect at right angle.
The midpoint of the side of a triangle are joined together to get four triangles. These four triangles are:
not equal to each other
congruent to each other
not congruent to each other
none of these
In the given figure, AB || CD || EF and E is the mid-point of side AD, then :

OE : OF = 1 : 3
OE = OF
OF = 2 x OE
CF = FB
In rhombus PQRS; A, B and C are mid-points of sides PQ, QR and RS respectively. If ∠P = 60°, the angle PQR is equal to:

60°
90°
120°
none of these