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In the given figure, AB is the largest chord of the circle, AB = 18 cm and the length of the chord CD is half of length of chord AB, then :

In the given figure, AB is the largest chord of the circle, AB = 18 cm and the length of the chord CD is half of length of chord AB, then. Circles, Concise Mathematics Solutions ICSE Class 8.
  1. OP = 18 cm and CD = 18 cm

  2. OP = 9 cm and CD = 18 cm

  3. OP = 18 cm and CD = 9 cm

  4. OP = 9 cm and CD = 9 cm

Circles

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Answer

As we know that

the largest chord of a circle is its diameter.

Diameter, AB = 20 cm

Chord CD = half of length of chord AB = 12×18\dfrac{1}{2} \times 18

= 9 cm.

OP is radius of the circle. So, radius is half of the diameter.

OP = 12×18\dfrac{1}{2} \times 18 = 9 cm

∴ OP = 9 cm and CD = 9 cm

Hence, option 4 is the correct option.

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