Mathematics
In the given figure, △ABD ≅ △ACD. If ∠DAC = 30° and ∠BDC = 110°, then the measure of ∠DBA is :

30°
50°
70°
25°
Related Questions

Assertion (A): In △ABC, D is a point on side BC. AB + BC + AC > 2AD
Reason (R): Sum of two sides of a triangle is greater than the third side.
A is true, R is false
A is false, R is true
Both A and R are true
Both A and R are false
In the given figure, the bisectors of ∠B and ∠C intersect each other at O and ∠BAC = 50°. The measure of ∠BOC is :

100°
115°
130°
140°
ABC is a triangle in which AC = BC and ∠BAC = 50°. Side BC is produced to D such that BC = CD. ∠BAD is equal to :
45°
50°
90°
100°
ABD is a triangle such that ∠ADB = 20° and C is a point on BD such that AB = AC and CD = CA. The measure of ∠ABC :
40°
50°
55°
60°