Mathematics
In the given figure, ∠BAP = ∠DCP = 70°, PC = 6 cm and CA = 4 cm, then PD : DB is equal to:
5 : 3
3 : 5
3 : 2
2 : 3
Related Questions
ΔABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. ΔDEF ∼ ΔABC. If EF = 4 cm, then the perimeter of ΔDEF is :
7.5 cm
15 cm
22.5 cm
30 cm
In ΔABC, DE is drawn parallel to BC cutting the other two sides at D and E. If AB = 3.6 cm, AC = 2.4 cm and AD = 2.1 cm, then AE is equal to:
1.05 cm
1.2 cm
1.4 cm
1.8 cm
In the adjoining figure, DE ∥ BC. If AD : DB = 3 : 1 and EA = 3.3 cm, then AC equals:
1.1 cm
4 cm
4.4 cm
5.5 cm
In the adjoining figure, ∠ADE = ∠ABC, AE = 8 cm, EB = 7 cm, BC = 9 cm, AD = 10 cm and DC = 2 cm. Then the length of DE is:
6 cm
6.75 cm
7.8 cm
13.5 cm
