In the given figure, DE ∥ BC and DE : BC = 3 : 5. alculate ar(ΔADE) : ar(trap. BCED).
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In the given figure, DE ∥ BC and DE : BC = 3 : 5. alculate ar(ΔADE) : ar(trap. BCED).

KnowledgeBoat · Accepted Answer

It is given that DE BC. ∠ADE = ∠ABC [Corresponding angles are equal] ∠AED = ∠ACB [Corresponding angles are equal] ΔADE ΔАВС (By A.A. axiom) We know that, The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Subtracting 1 from both sides, we get: Hence, ar(ΔADE) : ar(trap. BCED) = 9 : 16.

Mathematics

In the given figure, DE ∥ BC and DE : BC = 3 : 5. alculate ar(ΔADE) : ar(trap. BCED).

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Related Questions

In the given figure, BC ∥ DE, area (ΔABC) = 25 cm², area (trap. BCED) = 24 cm² and DE = 14 cm. Calculate the length of BC.

In ΔABC, D and E are mid-points of AB and AC respectively.
Find: ar(ΔADE) : ar(ΔABC).

Mathematics

In the given figure, DE ∥ BC and DE : BC = 3 : 5. alculate ar(ΔADE) : ar(trap. BCED).

Similarity

Related Questions

In the given figure, BC ∥ DE, area (ΔABC) = 25 cm2, area (trap. BCED) = 24 cm2 and DE = 14 cm. Calculate the length of BC.

In ΔABC, D and E are mid-points of AB and AC respectively.Find: ar(ΔADE) : ar(ΔABC).

In the given figure, BC ∥ DE, area (ΔABC) = 25 cm², area (trap. BCED) = 24 cm² and DE = 14 cm. Calculate the length of BC.

In ΔABC, D and E are mid-points of AB and AC respectively.
Find: ar(ΔADE) : ar(ΔABC).