Mathematics

In the given figure, PAB is a secant to the circle and PT is a tangent at T. Prove that:

(i) ∠PAT ∼ ∠PTB

(ii) PA × PB = PT2

In the given figure, PAB is a secant to the circle and PT is a tangent at T. Prove that. Tangent Properties of Circles, RSA Mathematics Solutions ICSE Class 10.

Circles

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