Mathematics
In the given figure, if sides AB, BC, CD and DA of a quadrilateral ABCD touch a circle at points P, Q, R and S respectively, then CR + PB =
BC
AB
CD
AD
Circles
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Answer
Tangents drawn from the same external point to a circle are equal.
From B,
BP = BQ ……..(1)
From C,
CR = CQ ……….(2)
Adding equation (1) and (2), we get :
∴ CR + PB = CQ + BQ = BC
Hence, option 1 is the correct option.
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