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Mathematics

For the given frequency distribution, the adjustment factor is :

C.I.f
30-348
34-3810
38-428
  1. 38342\dfrac{38 - 34}{2}

  2. 30+342\dfrac{30 + 34}{2}

  3. 0

  4. 34 + 38

Statistics

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Answer

By formula,

Adjustment factor = Lower limit of one class - Upper limit of previous class2\dfrac{\text{Lower limit of one class - Upper limit of previous class}}{2}

The given classes (30-34, 34-38, 38-42) are already in continuous (exclusive) form, as the upper limit of each class is equal to the lower limit of the next class.

⇒ Adjustment factor = 34342=02=0\dfrac{34 - 34}{2} = \dfrac{0}{2} = 0.

Hence, Option 3 is the correct option.

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