5 + x ≤ 2x < x - 2, x ∈ R.

Statement (1) : There is no value of x ∈ R that satisfies the given inequation.

Statement (2) : 5 + x - x ≤ 2x - x < x - 2 - x ⇒ 5 ≤ x < -2

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.

Solve the inequation :

$12 + 1\dfrac{5}{6}x \le 5 + 3x$ and x ∈ R.

Find the set of values of x, satisfying :

7x + 3 ≥ 3x - 5 and $\dfrac{x}{4} - 5 \le \dfrac{5}{4} - x$, where x ∈ N.

Solve :

(i) $\dfrac{x}{2} + 5 \le \dfrac{x}{3} + 6$, where x is a positive odd integer

(ii) $\dfrac{2x + 3}{3} \ge \dfrac{3x - 1}{4}$, where x is a positive even integer