Govind spends ₹ 8,100 in buying some jeans at ₹ 1,200 each and some shirts at ₹ 300 each. The ratio of the number of shirts to that of jeans, when the maximum possible number of jeans is purchased is:

1. 1 : 2

2. 1 : 4

3. 2 : 1

4. 5 : 7

Let the number of jeans Gopal brought be x and shirts be y.

Given,

Cost of jeans = ₹ 1,200.

Cost of shirt = ₹ 300.

Total amount spent = ₹ 8,100.

⇒ 1200x + 300y = 8100

⇒ 1200x + 300y - 8100 = 0

⇒ 300(4x + y - 27) = 0

⇒ 4x + y - 27 = 0

To maximize x keep y ≥ 0

⇒ 4x = 27

Maximum value of x can be 6.

Substitute value of x to get y,

⇒ 4(6) + y - 27 = 0

⇒ 24 + y - 27 = 0

⇒ y - 3 = 0

⇒ y = 3.

Ratio of shirt(y) : jeans(x) = 3 : 6 = 1 : 2.

Hence, option 1 is the correct option.