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Chemistry

How is acetic acid prepared from

(a) Ethanol

(b) Acetylene

Organic Chemistry

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Answer

(a) Ethanol under high pressure and low temperature when treated with oxidising agent like acidified potassium dichromate produces ethanoic acid (acetic acid).

C2H5OH ethanol[ethyl alcohol]K2Cr2O7[O]CH3CHOethanal [acetaldehyde] K2Cr2O7[O]CH3COOHethanoic acid[acetic acid]\underset{ \text{ ethanol[ethyl alcohol]}}{\text{C}2\text{H}5\text{OH}} \xrightarrow[\text{K}2\text{Cr}2\text{O}7]{\text{[O]}} \underset{\text{ethanal [acetaldehyde] }}{\text{CH}3\text{CHO}} \xrightarrow[\text{K}2\text{Cr}2\text{O}7]{\text{[O]}} \underset{ \text{ethanoic acid[acetic acid]} }{\text{CH}3\text{COOH}}

(b) Acetylene is first converted to acetaldehyde by passing it through a 40 percent H2SO4 solution at 60°C in the presence of 1% Mercury(II) Sulphate [HgSO4].

C2H2acetylene+H2OH2SO4(dil) , HgSO4CH3CHOethanal [acetaldehyde] \underset{\text{acetylene}}{\text{C}2\text{H}2} + \text{H}2\text{O} \xrightarrow{\text{H}2\text{SO}4\text{(dil) , HgSO}4}\underset{\text{ethanal [acetaldehyde] }}{\text{CH}_3\text{CHO}}

The acetaldehyde is oxidised to acetic acid by passsing a mixture of acetaldehyde vapous and air over manganese acetate at 70°C

2CH3CHOethanal [acetaldehyde] +O2CatalystΔ2CH3COOHethanoic acid[acetic acid]\underset{\text{ethanal [acetaldehyde] }}{2\text{CH}3\text{CHO}} + \text{O}2 \xrightarrow[\text{Catalyst}]{\Delta} \underset{ \text{ethanoic acid[acetic acid]} }{2\text{CH}_3\text{COOH}}

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