Mathematics
How many terms are there in the series :
4, 7, 10, 13, ……….., 148 ?
AP
37 Likes
Answer
Since, 7 - 4 = 3, 10 - 7 = 3 and 13 - 10 = 3.
Hence, the series is an A.P. with common difference = 3 and last term = 148.
nth term of an A.P. is given by,
an = a + (n - 1)d
⇒ 148 = 4 + (n - 1)3
⇒ 148 = 4 + 3n - 3
⇒ 148 = 3n + 1
⇒ 148 - 1 = 3n
⇒ 3n = 147
⇒ n = 49.
Hence, no. terms in the series = 49.
Answered By
21 Likes