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Mathematics

If 2x.3y.5z = 2160, find the values of x, y and z. Hence, compute the value of 3x.2-y.5-z.

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Answer

2160 = 24.33.51.

∴ 24.33.51 = 2x.3y.5z.

∴ x = 4, y = 3 and z = 1.

Substituting values of x, y and z in 3x.2-y.5-z

=34×23×51=81×123×15=81×18×15=8140=2140.= 3^4 \times 2^{-3} \times 5^{-1} \\[1em] = 81 \times \dfrac{1}{2^3} \times \dfrac{1}{5} \\[1em] = 81 \times \dfrac{1}{8} \times \dfrac{1}{5} \\[1em] = \dfrac{81}{40} = 2\dfrac{1}{40}.

Hence, x = 4, y = 3 and z = 1 and 3x.2-y.5-z = 2140.2\dfrac{1}{40}.

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