If a > b, then for two 3-digit numbers abc and cba; we have abc - cba equal to :
-27
-6
6
none of these
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abc - cba
= (100a + 10b + c) - (100c + 10b + a)
= 100a + 10b + c - 100c - 10b - a
= (100a - a) + (10b - 10 x b) + (c - 100c)
= 99a - 99 x c
= 99(a - c)
Hence, option 4 is the correct option.
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In a 2-digit number ab and a > b then ab - ba is equal to :
0
9(a - b)
9(b - a)
If a = b, then ab ÷ ba is equal to :
11(a + b)
Without actual calculation, the quotient, when the sum of 59 and 95 is divided by 11, is :
14
9
95 – 59