If a = c^z, b = a^x and c = b^y, prove that xyz = 1.

Given,

a = c^z, b = a^x and c = b^y

Substituting value of c in a = c^z we get,

⇒ a = (b^y)^z = b^yz

Substituting value of b in above equation we get,

⇒ a = (a^x)^yz
⇒ a = a^xyz

∴ xyz = 1.

Hence, proved that xyz = 1.