If A = [5−270] and B=[83]\begin{bmatrix}[r] 5 & -2 \ 7 & 0 \end{bmatrix} \text{ and B} = \begin{bmatrix}[r] 8 \ 3 \end{bmatrix}[57−20] and B=[83], then which of the following is not possible ?
A2
AB
BA
15A
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BA is not possible because no. of columns in B (1) is not equal to the no. of rows in A (2).
Hence, Option 3 is the correct option.
Answered By
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If A = [4x01],B=[21201]\begin{bmatrix}[r] 4 & x \ 0 & 1 \end{bmatrix}, B = \begin{bmatrix}[r] 2 & 12 \ 0 & 1 \end{bmatrix}[40x1],B=[20121] and A = B2, the value of x is :
38
-6
-36
36
A, B and C are three square matrices each of order 3; the order of matrix CA + B2 is :
3 × 1
3 × 3
1 × 3
2 × 3
If A = [1011],B=[0110] and C=[1100]\begin{bmatrix}[r] 1 & 0 \ 1 & 1 \end{bmatrix}, B = \begin{bmatrix}[r] 0 & 1 \ 1 & 0 \end{bmatrix}\text{ and C} = \begin{bmatrix}[r] 1 & 1 \ 0 & 0 \end{bmatrix}[1101],B=[0110] and C=[1010], the matrix A2 + 2B - 3C is :
[−2−141]\begin{bmatrix}[r] -2 & -1 \ 4 & 1 \end{bmatrix}[−24−11]
[2−141]\begin{bmatrix}[r] 2 & -1 \ 4 & 1 \end{bmatrix}[24−11]
[2141]\begin{bmatrix}[r] 2 & 1 \ 4 & 1 \end{bmatrix}[2411]
[21−4−1]\begin{bmatrix}[r] 2 & 1 \ -4 & -1 \end{bmatrix}[2−41−1]
Evaluate : if possible :
[32][20]\begin{bmatrix}[r] 3 & 2 \ \end{bmatrix}\begin{bmatrix}[r] 2 \ 0 \end{bmatrix}[32][20]
