If x=3mx = 3^mx=3m and y=3m+2,xyy = 3^{m + 2}, \dfrac{x}{y}y=3m+2,yx is:
9
19\dfrac{1}{9}91
6
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x=3mx = 3^mx=3m and y=3m+2y = 3^{m + 2}y=3m+2. Hence,
xy=3m3m+2=3m3m×32=132=19\dfrac{x}{y} = \dfrac{3^m}{3^{m + 2}}\\[1em] = \dfrac{3^m}{3^m \times 3^2}\\[1em] = \dfrac{1}{3^2}\\[1em] = \dfrac{1}{9}yx=3m+23m=3m×323m=321=91
Hence, option 2 is the correct option.
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If 1125 = 3m x 5n, find m and n.
Find x, if 9×3x=(27)2x−39 \times 3^x = (27)^{2x-3}9×3x=(27)2x−3
[x−23y−1]−1\Big[\dfrac{x^{-2}}{3y^{-1}}\Big]^{-1}[3y−1x−2]−1 is equal to:
3x2y\dfrac{3x^2}{y}y3x2
x23y\dfrac{x^2}{3y}3yx2
y3x2\dfrac{y}{3x^2}3x2y
3yx2\dfrac{3y}{x^2}x23y
If [45]−3×[45]−5=[45]3x−2\Big[\dfrac{4}{5}\Big]^{-3} \times \Big[\dfrac{4}{5}\Big]^{-5} = \Big[\dfrac{4}{5}\Big]^{3x - 2}[54]−3×[54]−5=[54]3x−2, the value of x is:
2
12\dfrac{1}{2}21
-2
−12-\dfrac{1}{2}−21