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Mathematics

If x=3mx = 3^m and y=3m+2,xyy = 3^{m + 2}, \dfrac{x}{y} is:

  1. 9

  2. 19\dfrac{1}{9}

  3. 6

  4. 9

Exponents

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Answer

x=3mx = 3^m and y=3m+2y = 3^{m + 2}. Hence,

xy=3m3m+2=3m3m×32=132=19\dfrac{x}{y} = \dfrac{3^m}{3^{m + 2}}\\[1em] = \dfrac{3^m}{3^m \times 3^2}\\[1em] = \dfrac{1}{3^2}\\[1em] = \dfrac{1}{9}

Hence, option 2 is the correct option.

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