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Mathematics

If x2x=3, then x38x3x - \dfrac{2}{x} = 3, \text{ then } x^3 - \dfrac{8}{x^3} is equal to

  1. 27

  2. 36

  3. 45

  4. 54

Expansions

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Answer

We know that,

(a - b)3 = a3 -3ab(a - b) - b3

⇒ a3 - b3 = (a - b)3 + 3ab(a - b)

x38x3=(x2x)3+6(x2x)\therefore x^3 - \dfrac{8}{x^3} = \Big(x - \dfrac{2}{x}\Big)^3 + 6\Big(x - \dfrac{2}{x}\Big)

Substituting values we get,

x38x3=33+6×3=27+18=45.x^3 - \dfrac{8}{x^3} = 3^3 + 6 \times 3 \\[1em] = 27 + 18 \\[1em] = 45.

Hence, Option 3 is the correct option.

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