Given 3 log x + $\dfrac{1}{2}$ log y = 2, express y in terms of x.

If log₂ (log₃ x) = 4, the value of x is :

1. 3¹⁶

2. 16³

3. 3 × 16

4. 16 ÷ 3

If log x - log (2x - 1) = 1, the value of x is :

1. $\dfrac{19}{10}$

2. 19 × 10

3. $\dfrac{10}{19}$

4. $\dfrac{1}{19 \times 10}$

If x = log $\dfrac{3}{5}, \text{ y = log } \dfrac{5}{4}\text{ and z = 2 log } \dfrac{\sqrt{3}}{2}$, the value of x + y - z is :

1. 1

2. -1

3. 2

4. 0