If log 2 x = a and log 5 y = a, write 100 2a - 1 in terms of x and y.

Given, log 2 x = a and log 5 y = a ⇒ x = 2 a and y = 5 a 100 2a - 1 = 100 2a .100 -1 = (100 a ) 2 .100 -1 = [(2 2 .5 2 ) a ] 2 .100 -1 = [(2 2a ).(5 2a )] 2 .100 -1 = [(2 a ) 2 .(5 a ) 2 ] 2 .(100) -1 = [x 2 .y 2 ] 2 .100 -1 = . Hence, 100 2a - 1 = .

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If log₂y = x and log₃z = x, find 72^x in terms of y and z.

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Simplify the following :
log a³ - log a²

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Simplify the following :
log a³ ÷ log a²

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Mathematics

If log₂x = a and log₅y = a, write 100^{2a - 1} in terms of x and y.

Logarithms

Related Questions

If log₂y = x and log₃z = x, find 72^x in terms of y and z.

Simplify the following :
log a³ - log a²

Simplify the following :
log a³ ÷ log a²

Mathematics

If log2x = a and log5y = a, write 1002a - 1 in terms of x and y.

Logarithms

Related Questions

If log2y = x and log3z = x, find 72x in terms of y and z.

Simplify the following :log a3 - log a2

Simplify the following :log a3 ÷ log a2

If log₂x = a and log₅y = a, write 100^{2a - 1} in terms of x and y.

If log₂y = x and log₃z = x, find 72^x in terms of y and z.

Simplify the following :
log a³ - log a²

Simplify the following :
log a³ ÷ log a²