Solve for x:

log₂ x + log₈ x + log₃₂ x = $\dfrac{23}{15}$

If $\text{log}_{\sqrt{3}} \space 27 = x$, then the value of x is

1. 3

2. 4

3. 6

4. 9

If log_0.5 64 = x, then the value of x is

1. -4

2. -6

3. 4

4. 6

If $\text{log}_{\sqrt[3]{5}} \space x$ = -3, then the value of x is

1. $\dfrac{1}{5}$

2. $-\dfrac{1}{5}$

3. -1

4. 5