If m n and (m + n)^-1 (m^-1 + n^-1) = m^xn^y; show that : x + y + 2 = 0

Question

KnowledgeBoat · Accepted Answer

Given, Substituting value in L.H.S. of equation x + y + 2 = 0, we get : ⇒ x + y + 2 = (-1) + (-1) + 2 = -2 + 2 = 0. Since, L.H.S. = R.H.S. = 0. Hence, proved that x + y + 2 = 0.

Mathematics

If m ≠ n and (m + n)^-1 (m^-1 + n^-1) = m^xn^y;
show that : x + y + 2 = 0

Indices

Related Questions

If 5^{x + 1} = 25^{x - 2}; find the value of :
3^{x - 3} × 2^{3 - x}.

If 4^{x + 3} = 112 + 8 × 4^x; find (18x)^3x.

Mathematics

If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny;show that : x + y + 2 = 0

Indices

Related Questions

If 5x + 1 = 25x - 2; find the value of :3x - 3 × 23 - x.

If 4x + 3 = 112 + 8 × 4x; find (18x)3x.

If m ≠ n and (m + n)^-1 (m^-1 + n^-1) = m^xn^y;
show that : x + y + 2 = 0

If 5^{x + 1} = 25^{x - 2}; find the value of :
3^{x - 3} × 2^{3 - x}.

If 4^{x + 3} = 112 + 8 × 4^x; find (18x)^3x.