If one root of equation (p - 3)x² + x + p = 0 is 2, the value of p is :
-2
2
±2
1 and 2

Question

If one root of equation (p - 3)x² + x + p = 0 is 2, the value of p is : 1. -2 2. 2 3. 2 4. 1 and 2

KnowledgeBoat · Accepted Answer

Given, One root of equation (p - 3)x² + x + p = 0 is 2. ∴ x = 2 satisfies the equation. ∴ (p - 3)(2)² + 2 + p = 0 ⇒ 4(p - 3) + 2 + p = 0 ⇒ 4p - 12 + 2 + p = 0 ⇒ 5p - 10 = 0 ⇒ 5p = 10 ⇒ p = = 2. Hence, Option 2 is the correct option.

Mathematics

If one root of equation (p - 3)x² + x + p = 0 is 2, the value of p is :
-2
2
±2
1 and 2

Quadratic Equations

Related Questions

The roots of the quadratic equation x² - 6x - 7 = 0 are :
-1 and 7
1 and 7
-1 or 7
1 and -7

The roots of the quadratic equation x(x + 8) + 12 = 0 are :
6 or 2
-6 or -2
6 and -2
-6 and -2

Mathematics

If one root of equation (p - 3)x2 + x + p = 0 is 2, the value of p is :-22±21 and 2

Quadratic Equations

Related Questions

The roots of the quadratic equation x2 - 6x - 7 = 0 are :-1 and 71 and 7-1 or 71 and -7

The roots of the quadratic equation x(x + 8) + 12 = 0 are :6 or 2-6 or -26 and -2-6 and -2

If one root of equation (p - 3)x² + x + p = 0 is 2, the value of p is :
-2
2
±2
1 and 2

The roots of the quadratic equation x² - 6x - 7 = 0 are :
-1 and 7
1 and 7
-1 or 7
1 and -7

The roots of the quadratic equation x(x + 8) + 12 = 0 are :
6 or 2
-6 or -2
6 and -2
-6 and -2