If the mean of the data given in adjoining table is 20, the relation between x 1 and x 2 is : x | f | fx -- | --- | --- 10 | x 1 | 20 | 20 | 30 | x 2 | 1. x 1 + x 2 = 30 2. x 1 - x 2 = 15 3. x 1 - x 2 = 0 4. x 1 + x 2 = 20

x | f | fx -- | --- | --- 10 | x 1 | 10x 1 20 | 20 | 400 30 | x 2 | 30x 2 Total | Σf = 20 + x 1 + x 2 | Σfx = 400 + 10x 1 + 30x 2 By formula, Mean = Substituting values we get : Hence, Option 3 is the correct option.

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Mathematics

If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20

x	f	fx
10	x₁
20	20
30	x₂

Statistics

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C.I.	f	x	u = (x - A)/i	f × u
0-10	5
10-20	10
20-30	10

Age (years)	No. of students
16 - 18	2
18 - 20	7
20 - 22	21
22 - 24	17
24 - 26	3

Mathematics

If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20

Statistics

Related Questions

For data given in the adjoining table, the mean is :
C.I. f x u = (x - A)/i f × u
0-10 5
10-20 10
20-30 10
17
27
25
60

The mean of observations, given in the adjoining table, is 24, the value of a is :
x f
10 10
20 a
30 30
20
30
10
25

The mean of data, represented by given diagram is :
53
47
42
51

The following table gives the ages of 50 students of a class. Find the arithmetic mean of their ages.
Age (years) No. of students
16 - 18 2
18 - 20 7
20 - 22 21
22 - 24 17
24 - 26 3

Mathematics

If the mean of the data given in adjoining table is 20, the relation between x1 and x2 is :xffx10x1202030x2x1 + x2 = 30x1 - x2 = 15x1 - x2 = 0x1 + x2 = 20

Statistics

Related Questions

For data given in the adjoining table, the mean is :C.I.fxu = (x - A)/if × u0-10510-201020-301017272560

The mean of observations, given in the adjoining table, is 24, the value of a is :xf101020a303020301025

The mean of data, represented by given diagram is :53474251

The following table gives the ages of 50 students of a class. Find the arithmetic mean of their ages.Age (years)No. of students16 - 18218 - 20720 - 222122 - 241724 - 263

If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20

For data given in the adjoining table, the mean is :
C.I. f x u = (x - A)/i f × u
0-10 5
10-20 10
20-30 10
17
27
25
60

The mean of observations, given in the adjoining table, is 24, the value of a is :
x f
10 10
20 a
30 30
20
30
10
25

The mean of data, represented by given diagram is :
53
47
42
51

The following table gives the ages of 50 students of a class. Find the arithmetic mean of their ages.
Age (years) No. of students
16 - 18 2
18 - 20 7
20 - 22 21
22 - 24 17
24 - 26 3