Mathematics
If the replacement set is the set of natural numbers, solve:
(i) x - 5 < 0
(ii) x + 1 ≤ 7
(iii) 3x - 4 > 6
(iv) 4x + 1 ≥ 17
Related Questions
Assertion (A) : x < -2 and x ≥ 1.
⇒ Solution set S = {x | -2 < x ≤ 1, x ∈ R}
Reason (R) : Two inequations can be written in a combined expression.
Both A and R are correct, and R is the correct explanation for A.
Both A and R are correct, and R is not the correct explanation for A.
A is true, but R is false.
A is false, but R is true.
Assertion (A) : The solution set in the system of negative integers for : 0 > -4 - p is {-3, -2. -1}.
Reason (R) : If the same quantity is subtracted from both sides of an equation, the symbol of inequality is reversed.
Both A and R are correct, and R is the correct explanation for A.
Both A and R are correct, and R is not the correct explanation for A.
A is true, but R is false.
A is false, but R is true.
If the replacement set = {-6, -3, 0, 3, 6, 9}, find the truth set of the following:
(i) 2x - 1 > 9
(ii) 3x + 7 ≤ 1
Solve: 9x - 7 ≤ 28 + 4x; x ∈ W.