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Mathematics

If x = 1 is a root of the equation x+kx2\sqrt{x} + kx - 2 = 0; the value of k is :

  1. 1

  2. -1

  3. 2

  4. -2

Quadratic Equations

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Answer

Given,

x = 1 is a root of the equation x+kx2\sqrt{x} + kx - 2 = 0.

1+k(1)2=01+k2=0k1=0k=1.\Rightarrow \sqrt{1} + k(1) - 2 = 0 \\[1em] \Rightarrow 1 + k - 2 = 0 \\[1em] \Rightarrow k - 1 = 0 \\[1em] \Rightarrow k = 1.

Hence, Option 1 is the correct option.

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