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Mathematics

If x = 2 and y = 1 ; find the value of (-4x2y3) x (-5x2y5).

Algebraic Expressions

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Answer

(-4x2y3) ×\times (-5x2y5)

= (-4) ×\times (-5)x(2+2)y(3+5)

= 20 x4y8

When x = 2 and y = 1,

= 20 x 24 x 18

= 20 x 16 x 1

= 320

Hence, if x = 2 and y = 1 ; the value of (-4x2y3) x (-5x2y5) = 320.

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