Solve the following pairs of linear equations:

$\dfrac{1}{2(2x + 3y)} + \dfrac{12}{7(3x - 2y)} = \dfrac{1}{2}$

$\dfrac{7}{2x + 3y} + \dfrac{4}{3x - 2y} = 2$

Solve the following pairs of linear equations:

$\dfrac{1}{2(x + 2y)} + \dfrac{5}{3(3x - 2y)} = -\dfrac{3}{2}$

$\dfrac{5}{4(x + 2y)} - \dfrac{3}{5(3x - 2y)} = \dfrac{61}{60}$

The solution of the pair of linear equations 2x - y = 5 and 5x - y = 11 is

1. x = -1, y = 2

2. x = 2, y = -1

3. x = 0, y = -5

4. x = $\dfrac{5}{2}$, y = 0

If x = a, y = b is the solution of the equations x - y = 2 and x + y = 4, then the values of a and b are respectively,

1. 3 and 5

2. 5 and 3

3. 3 and 1

4. -1 and -3