If x and y vary directly, find the values of x, y and z :

x	y
3	36
x	60
y	96
10	z

Since a and b vary directly,

$\dfrac{3}{36} = \dfrac{x}{60} = \dfrac{y}{96} = \dfrac{10}{z}\\[1em] \Rightarrow \dfrac{3}{36} = \dfrac{x}{60}, \dfrac{3}{36} = \dfrac{y}{96} \text{ and } \dfrac{3}{36} = \dfrac{10}{z}\\[1em] \Rightarrow x = \dfrac{3 \times 60}{36}, y = \dfrac{3 \times 96}{36} \text{ and } z = \dfrac{36 \times 10}{3}\\[1em] \Rightarrow x = \dfrac{180}{36} , y = \dfrac{288}{36} \text{ and } z = \dfrac{360}{3}\\[1em] \Rightarrow x = 5, y = 8 \text{ and } z = 120$

Hence, x = 5, y = 8 and z = 120.