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Mathematics

If x is a negative integer, find the solution set of 23+13(x+1)>0\dfrac{2}{3}+\dfrac{1}{3} (x + 1) \gt 0.

Linear Inequations

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Answer

Given,

23+13(x+1)>023+x3+13>0x3+1>0x3>1x>3\dfrac{2}{3}+\dfrac{1}{3} (x + 1) \gt 0 \\[0.5em] \Rightarrow \dfrac{2}{3} +\dfrac{x}{3} + \dfrac{1}{3} \gt 0 \\[0.5em] \Rightarrow \dfrac{x}{3} + 1 \gt 0 \\[0.5em] \Rightarrow \dfrac{x}{3} \gt – 1 \\[0.5em] \Rightarrow x \gt -3

x is a negative integer Solution set = {-2, –1}.

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