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Mathematics

If x = log 35, y = log 54 and z = 2log 32\dfrac{3}{5}, \text{ y = log }\dfrac{5}{4}\text{ and z = 2log }\dfrac{\sqrt{3}}{2}, find the values of

(i) x + y - z

(ii) 3x + y - z

Logarithms

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Answer

Given,

x+yz=log 35+log 542log 32=log 3 - log 5 + log 5 - log 4 - 2(log 3log 2)=log 3 - log 4 - 2log 312+2log 2=log 3 - log 222×12log 3 + 2log 2=log 3 - 2log 2 - log 3 + 2log 2=0.\Rightarrow x + y - z = \text{log }\dfrac{3}{5} + \text{log }\dfrac{5}{4} - 2\text{log }\dfrac{\sqrt{3}}{2} \\[1em] = \text{log 3 - log 5 + log 5 - log 4 - 2(log }\sqrt{3} - \text{log 2)} \\[1em] = \text{log 3 - log 4 - 2log 3}^{\dfrac{1}{2}} + \text{2log 2} \\[1em] = \text{log 3 - log 2}^2 - 2 \times \dfrac{1}{2}\text{log 3 + 2log 2} \\[1em] = \text{log 3 - 2log 2 - log 3 + 2log 2} \\[1em] = 0.

Hence, x + y - z = 0.

(ii) Given,

3x + y - z = 30 = 1.

Hence, 3x + y - z = 1.

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