If x⁴y²z³ = 49392, find the values of x, y and z, where x, y and z are different positive primes.

On prime factorization of 49392 we get,

49392 = 2⁴3²7³

∴ x⁴y²z³ = 2⁴3²7³

On comparing we get,

x = 2, y = 3 and z = 7.

Hence, x = 2, y = 3 and z = 7.