Science
The below image shows a corrective measure for a particular defect of vision.

(a) Identify the defect of vision and state what kind of lens is used to correct this deficiency.
(b) Draw and label a ray diagram that shows the defect of vision in the above case before correction.
Refraction Lens
1 Like
Answer
(a) The defect of vision shown is hypermetropia (long-sightedness).
Explanation : In this defect, the eye cannot focus clearly on near objects because the image of a nearby object is formed behind the retina so to correct this, a convex (converging) lens is used in front of the eye. The convex lens first converges the diverging rays from the near object so that, after refraction through the eye lens, the image forms exactly on the retina
(b) The labelled ray diagram showing hypermetropia defect is given below :

Answered By
1 Like
Related Questions
You are given four resistors each having resistance of R ohm. Find the maximum and minimum resistance that can be made with these four resistors.
A copper wire has a length L = 2 m, a cross-sectional area A = 0.5 mm2, and resistivity ρ = 1.7 × 10-8 Ωm. Calculate the resistance of another wire made of the same material whose length is twice the length of the wire but has the same cross-sectional area.
(a) What is dispersion of light?
(b) Explain the condition under which dispersion happens?
(c) Give one reason that causes presbyopia.
A student needs to make a 0.12 Ω resistor. She has some copper wire of 0.80 mm diameter. Resistivity of copper is 1.8 × 10–8 Ωm
(a) Determine the cross-sectional area of the wire.
(b) Calculate the length of wire required for the 0.12 Ω resistor