In a Science test given to a group of students, the marks scored by them (out of 100) are

41, 39, 52, 48, 54, 62, 46, 52, 40, 96, 42, 40, 98, 60, 52.

Find the mean and median of this data.

By formula,

$\text{Mean} = \dfrac{\text{Total marks}}{\text{No. of students}}$

Total marks = 41 + 39 + 52 + 48 + 54 + 62 + 46 + 52 + 40 + 96 + 42 + 40 + 98 + 60 + 52
= 822

$\text{Mean} = \dfrac{822}{15} \\[1em] = 54.8$

Given,

Student's marks : 41, 39, 52, 48, 54, 62, 46, 52, 40, 96, 42, 40, 98, 60, 52.

On arranging the marks obtained by the students in ascending order, we have :

39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98

Here, n = 15 which is odd.

By formula,

$\text{Median } = \dfrac{n + 1}{2} \text{ th observation} \\[1em] = \dfrac{15 + 1}{2} \text{ th observation} \\[1em] = \dfrac{16}{2} \text{ th observation} \\[1em] = 8 \text{ th observation} \\[1em] = 52.$

Hence, mean = 54.8 and median = 52.