In a single throw of a die, find the probability of getting :

(i) 8

(ii) a number greater than 8

(iii) a number less than 8

(i) Total number of possible outcomes = 6 (1, 2, 3, 4, 5 and 6)

Number of favourable outcomes (Getting 8) = 0

P(Getting 8) = $\dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

= $\dfrac{0}{6}$

= 0

Hence, the probability of getting 8 is 0.

(ii) Total number of possible outcomes = 6 (1, 2, 3, 4, 5 and 6)

Number of favourable outcome (Getting a number greater than 8) = 0

P(Getting a number greater than 8) = $\dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

= $\dfrac{0}{6}$

= 0

Hence, the probability of getting a number greater than 8 is 0.

(iii) Total number of possible outcomes = 6 (1, 2, 3, 4, 5 and 6)

Number of favourable outcomes (Getting a number less than 8) = 6 (1, 2, 3, 4, 5 and 6)

P(Getting a number less than 8) = $\dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

= $\dfrac{6}{6}$

= 1

Hence, the probability of getting a number less than 8 is 1.