In an examination, 92% of the candidates passed and 96 failed. Find the number of candidates who appeared for this exam.

Percent of candidates who passed the exam = 92%

Percent of candidates who failed the exam = (100% - 92%) = 8%

Number of candidates who failed the exam = 96

Let the total number of candidates be $x$.

$\therefore 8\% \text{ of } x = 96\\[1em] ⇒ \dfrac{8}{100} \times x = 96\\[1em] ⇒ x = \dfrac{96 \times 100}{8}\\[1em] ⇒ x = \dfrac{9600}{8}\\[1em] ⇒ x = 1200$ Hence, total number of candidates who appeared for exam = 1200.