Physics
In an experiment, 17 g of ice is used to bring down the temperature of 40 g of water at 34° C to it's freezing temperature. The specific heat capacity of water is 4.2 J g-1 K-1. Calculate the specific latent heat of ice. State one important assumption made in the above calculation.
Calorimetry
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Answer
Given,
Mass of ice (m1) = 17 g
Mass of water (m2) = 40 g
Change in temperature = 34 – 0 = 34° C = 34 K
Specific heat capacity of water (c) = 4.2 J g-1 K-1
specific latent heat of ice = ?
Assuming that no heat energy is lost,
heat energy required by ice to melt = heat energy given by water
So,
m1 x L = m2 x c x change in temperature
Substituting the values in the relation above we get,
Hence, specific latent heat of ice = 336 J g-1
Assumption — There is no loss of energy.
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