In each of the following cases, find the least value/values of letters used in place of digits :

$\begin{matrix} & 9 & 8 \ + & 4 & \text{A} \ \hline \text{C} & \text{B} & 3 \ \hline \end{matrix}$

$\begin{matrix} & 9 & 8 \ + & 4 & \text{A} \ \hline \text{C} & \text{B} & 3 \ \hline \end{matrix}$

Firstly, we will find the value of A.

Clearly, 8 + A is a number whose ones digit is 3.

⇒ 8 + A = 3, 8 + A = 13, 8 + A = 23; and so on.

⇒ A = 3 - 8 , A = 13 - 8, A = 23 - 8; and so on.

⇒ A = -5 , A = 5, A = 15; and so on.

Since, A is a digit. ∴ A = 5

$\begin{matrix} & \overset{1}{9} & 8 \ + & 4 & \text{5} \ \hline \text{C} & \text{B} & 3 \ \hline \end{matrix}$ Secondly, we will find the value of B

1 + 9 + 4 = B

14 = B

Since, B is a digit. ∴ B = 4 and hence, C = 1

$\begin{matrix} & 9 & 8 \ + & 4 & \text{5} \ \hline \text{1} & \text{4} & 3 \ \hline \end{matrix}$ A = 5, B = 4 and C = 1