Mathematics
In figure (1) given below, point D divides the side BC of ∆ABC in the ratio m : n. Prove that area of ∆ABD : area of ∆ADC = m : n.
Related Questions
In the figure (2) given below, P is a point on the side BC of ∆ABC such that PC = 2BP, and Q is a point on AP such that QA = 5PQ, find area of ∆AQC : area of ∆ABC.
In the figure (3) given below, AD is a median of △ABC and P is a point in AC such that area of △ADP : area of △ABD = 2 : 3. Find
(i) AP : PC
(ii) area of △PDC : area of △ABC
