Mathematics
In the figure, given alongside, AM bisects angle A and DM bisects angle D of parallelogram ABCD. Prove that : ∠AMD = 90°.
Related Questions
If the diagonals of a quadrilateral bisect each other at right angle, the quadrilateral is :
square
rhombus
parallelogram
rectangle
State, 'true' or 'false' :
(i) The diagonals of a rectangle bisect each other.
(ii) The diagonals of a quadrilateral bisect each other.
(iii) The diagonals of a parallelogram bisect each other at right angle.
(iv) Each diagonal of a rhombus bisects it.
(v) The quadrilateral, whose four sides are equal, is a square.
(vi) Every rhombus is a parallelogram.
(vii) Every parallelogram is a rhombus.
(viii) Diagonals of a rhombus are equal.
(ix) If two adjacent sides of a parallelogram are equal, it is a rhombus.
(x) If the diagonals of a quadrilateral bisect each other at right angle, the quadrilateral is a square.
In the following figure, AE and BC are equal and parallel and the three sides AB, CD and DE are equal to one another. If angle A is 102°. Find angles AEC and BCD.
