In the figure (ii) given below, ∠D = ∠E and . Prove that ABC is an isosceles triangle.

Question

KnowledgeBoat · Accepted Answer

Given, ∠D = ∠E So, AD = AE [Sides opposite to equal angles] Given, Hence, by basic proportionality theorem, DE is parallel to BC. As AD = AE so in order to satisfy Eq 1, DB = EC. AB = AD + DB = AE + EC and AC = AE + EC. Hence, AB = AC which means ABC is an isosceles triangle.

Mathematics

In the figure (ii) given below, ∠D = ∠E and . Prove that ABC is an isosceles triangle.

Similarity

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