Mathematics
In the given figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that : (i) Δ ABC ~ Δ AMP (ii) CA/PA = BC/MP
Related Questions
In the given figure, altitudes AD and CE of ∆ ABC intersect each other at the point P. Show that:
(i) ∆ AEP ~ ∆ CDP
(ii) ∆ ABD ~ ∆ CBE
(iii) ∆ AEP ~ ∆ ADB
(iv) ∆ PDC ~ ∆ BEC
E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that △ ABE ~ △ CFB.
In the figure, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD ⊥ BC and EF ⊥ AC, prove that △ ABD ~ △ ECF.
