In the given figure, QR/QS = QT/PR and ∠1 = ∠2. Show that △ PQS ~ △ TQR.

Question

KnowledgeBoat · Accepted Answer

In Δ PQR, ∠1 = ∠2 (Given) ⇒ PR = PQ (In a triangle sides opposite to equal angles are equal) In Δ PQS and Δ TQR ⇒ ∠PQS = ∠TQR (Both = ∠1) Given, Since, PR = PQ. ∴ Δ PQS ~ Δ TQR (By SAS criterion) Hence, proved that △ PQS ~ △ TQR.

Mathematics

In the given figure, QR/QS = QT/PR and ∠1 = ∠2. Show that △ PQS ~ △ TQR.

Triangles

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Mathematics

In the given figure, QR/QS = QT/PR and ∠1 = ∠2. Show that △ PQS ~ △ TQR.

Triangles

Related Questions

In given figure, △ ODC ~ △ OBA, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB.

S and T are points on sides PR and QR of △ PQR such that ∠P = ∠RTS. Show that △ RPQ ~ △ RTS.

In given figure, if △ ABE ≅ Δ ACD, show that△ ADE ∼ Δ ABC.

In given figure, if △ ABE ≅ Δ ACD, show that
△ ADE ∼ Δ ABC.