In the given figure, QR/QS = QT/PR and ∠1 = ∠2. Show that △ PQS ~ △ TQR.

In Δ PQR, ∠1 = ∠2 (Given) ⇒ PR = PQ (In a triangle sides opposite to equal angles are equal) In Δ PQS and Δ TQR ⇒ ∠PQS = ∠TQR (Both = ∠1) Given, Since, PR = PQ. ∴ Δ PQS ~ Δ TQR (By SAS criterion) Hence, proved that △ PQS ~ △ TQR.