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In the given figure, AOC is the diameter of the circle, with center O. If arc AXB is half of arc BYC, find ∠BOC.

In the given figure, AOC is the diameter of the circle, with center O. If arc AXB is half of arc BYC, find ∠BOC. Circle, Concise Mathematics Solutions ICSE Class 9.

Circles

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Answer

We know that,

Ratio of the angles subtended by the arcs on the center is equal to the ratio of the arcs.

AOBBOC=AXBBYCAOBBOC=12AOB=BOC2.\Rightarrow \dfrac{∠AOB}{∠BOC} = \dfrac{AXB}{BYC} \\[1em] \Rightarrow \dfrac{∠AOB}{∠BOC} = \dfrac{1}{2} \\[1em] \Rightarrow ∠AOB = \dfrac{∠BOC}{2}.

From figure,

⇒ ∠AOB + ∠BOC = 180°

BOC2\dfrac{∠BOC}{2} + ∠BOC = 180°

2BOC+BOC2\dfrac{2∠BOC + ∠BOC}{2} = 180°

3BOC2\dfrac{3∠BOC}{2} = 180°

⇒ ∠BOC = 23×180°=360°3\dfrac{2}{3} \times 180° = \dfrac{360°}{3} = 120°.

Hence, ∠BOC = 120°.

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