In the given figure, l // m // n and D is mid-point of CE. If AE = 12.6 cm, then BD is : 1. 12.6 cm 2. 25.2 cm 3. 6.3 cm 4. 18.9 cm

By mid-point theorem, The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and is equal to half of it. By converse of mid-point theorem, The straight line drawn through the mid-point of one side of a triangle parallel to another, bisects the third side. In △ AEC, Given, ⇒ m // n ∴ BD // AE. D is mid-point of CE. ∴ B is the mid-point of AC. (By converse of mid-point theorem) Also, ⇒ BD = = 6.3 cm Hence, Option 3 is the correct option.

ABCD is a quadrilateral in which AD = BC. E, F, G and H are the mid-points of AB, BD, CD and AC respectively. Prove that EFGH is a rhombus.

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The given figure shows a parallelogram ABCD in which E is mid-point of AD and DL // EB. Then, BF is equal to :
AD
BE
AE
AB

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Mathematics

In the given figure, l // m // n and D is mid-point of CE. If AE = 12.6 cm, then BD is :
12.6 cm
25.2 cm
6.3 cm
18.9 cm

Mid-point Theorem

Related Questions

ABCD is a quadrilateral in which AD = BC. E, F, G and H are the mid-points of AB, BD, CD and AC respectively. Prove that EFGH is a rhombus.

The given figure shows a parallelogram ABCD in which E is mid-point of AD and DL // EB. Then, BF is equal to :
AD
BE
AE
AB

Mathematics

In the given figure, l // m // n and D is mid-point of CE. If AE = 12.6 cm, then BD is :12.6 cm25.2 cm6.3 cm18.9 cm

Mid-point Theorem

Related Questions

ABCD is a quadrilateral in which AD = BC. E, F, G and H are the mid-points of AB, BD, CD and AC respectively. Prove that EFGH is a rhombus.

The given figure shows a parallelogram ABCD in which E is mid-point of AD and DL // EB. Then, BF is equal to :ADBEAEAB

In the given figure, l // m // n and D is mid-point of CE. If AE = 12.6 cm, then BD is :
12.6 cm
25.2 cm
6.3 cm
18.9 cm

The given figure shows a parallelogram ABCD in which E is mid-point of AD and DL // EB. Then, BF is equal to :
AD
BE
AE
AB